5(2c-4)=15+3c

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Solution for 5(2c-4)=15+3c equation:



5(2c-4)=15+3c
We move all terms to the left:
5(2c-4)-(15+3c)=0
We add all the numbers together, and all the variables
5(2c-4)-(3c+15)=0
We multiply parentheses
10c-(3c+15)-20=0
We get rid of parentheses
10c-3c-15-20=0
We add all the numbers together, and all the variables
7c-35=0
We move all terms containing c to the left, all other terms to the right
7c=35
c=35/7
c=5

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