5(2c-7)-3c=7(c-5)

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Solution for 5(2c-7)-3c=7(c-5) equation: 



5(2c-7)-3c=7(c-5)

We move all terms to the left:

5(2c-7)-3c-(7(c-5))=0

We add all the numbers together, and all the variables

-3c+5(2c-7)-(7(c-5))=0

We multiply parentheses

-3c+10c-(7(c-5))-35=0



We calculate terms in parentheses: -(7(c-5)), so:

7(c-5)

We multiply parentheses

7c-35

Back to the equation:

-(7c-35)



We add all the numbers together, and all the variables

7c-(7c-35)-35=0

We get rid of parentheses

7c-7c+35-35=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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