5(2c-8)=2(3c-10)

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Solution for 5(2c-8)=2(3c-10) equation:


Simplifying
5(2c + -8) = 2(3c + -10)

Reorder the terms:
5(-8 + 2c) = 2(3c + -10)
(-8 * 5 + 2c * 5) = 2(3c + -10)
(-40 + 10c) = 2(3c + -10)

Reorder the terms:
-40 + 10c = 2(-10 + 3c)
-40 + 10c = (-10 * 2 + 3c * 2)
-40 + 10c = (-20 + 6c)

Solving
-40 + 10c = -20 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
-40 + 10c + -6c = -20 + 6c + -6c

Combine like terms: 10c + -6c = 4c
-40 + 4c = -20 + 6c + -6c

Combine like terms: 6c + -6c = 0
-40 + 4c = -20 + 0
-40 + 4c = -20

Add '40' to each side of the equation.
-40 + 40 + 4c = -20 + 40

Combine like terms: -40 + 40 = 0
0 + 4c = -20 + 40
4c = -20 + 40

Combine like terms: -20 + 40 = 20
4c = 20

Divide each side by '4'.
c = 5

Simplifying
c = 5

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