5(2d+4)-5=35

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Solution for 5(2d+4)-5=35 equation: 



5(2d+4)-5=35

We move all terms to the left:

5(2d+4)-5-(35)=0

We add all the numbers together, and all the variables

5(2d+4)-40=0

We multiply parentheses

10d+20-40=0

We add all the numbers together, and all the variables

10d-20=0

We move all terms containing d to the left, all other terms to the right

10d=20

d=20/10

d=2

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