5(2d+9)=3(d+1)

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Solution for 5(2d+9)=3(d+1) equation: 



5(2d+9)=3(d+1)

We move all terms to the left:

5(2d+9)-(3(d+1))=0

We multiply parentheses

10d-(3(d+1))+45=0



We calculate terms in parentheses: -(3(d+1)), so:

3(d+1)

We multiply parentheses

3d+3

Back to the equation:

-(3d+3)



We get rid of parentheses

10d-3d-3+45=0

We add all the numbers together, and all the variables

7d+42=0

We move all terms containing d to the left, all other terms to the right

7d=-42

d=-42/7

d=-6

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