5(2d-3)=3(3d-5)

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Solution for 5(2d-3)=3(3d-5) equation: 



5(2d-3)=3(3d-5)

We move all terms to the left:

5(2d-3)-(3(3d-5))=0

We multiply parentheses

10d-(3(3d-5))-15=0



We calculate terms in parentheses: -(3(3d-5)), so:

3(3d-5)

We multiply parentheses

9d-15

Back to the equation:

-(9d-15)



We get rid of parentheses

10d-9d+15-15=0

We add all the numbers together, and all the variables

d=0

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