5(2e+1)=4e-(7-2e)

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Solution for 5(2e+1)=4e-(7-2e) equation: 



5(2e+1)=4e-(7-2e)

We move all terms to the left:

5(2e+1)-(4e-(7-2e))=0

We add all the numbers together, and all the variables

5(2e+1)-(4e-(-2e+7))=0

We multiply parentheses

10e-(4e-(-2e+7))+5=0



We calculate terms in parentheses: -(4e-(-2e+7)), so:

4e-(-2e+7)

We get rid of parentheses

4e+2e-7

We add all the numbers together, and all the variables

6e-7

Back to the equation:

-(6e-7)



We get rid of parentheses

10e-6e+7+5=0

We add all the numbers together, and all the variables

4e+12=0

We move all terms containing e to the left, all other terms to the right

4e=-12

e=-12/4

e=-3

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