5(2f+1)=-35

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Solution for 5(2f+1)=-35 equation: 



5(2f+1)=-35

We move all terms to the left:

5(2f+1)-(-35)=0

We add all the numbers together, and all the variables

5(2f+1)+35=0

We multiply parentheses

10f+5+35=0

We add all the numbers together, and all the variables

10f+40=0

We move all terms containing f to the left, all other terms to the right

10f=-40

f=-40/10

f=-4

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