5(2f+3)=2(5f+1)

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Solution for 5(2f+3)=2(5f+1) equation: 



5(2f+3)=2(5f+1)

We move all terms to the left:

5(2f+3)-(2(5f+1))=0

We multiply parentheses

10f-(2(5f+1))+15=0



We calculate terms in parentheses: -(2(5f+1)), so:

2(5f+1)

We multiply parentheses

10f+2

Back to the equation:

-(10f+2)



We get rid of parentheses

10f-10f-2+15=0

We add all the numbers together, and all the variables

13!=0

There is no solution for this equation

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