5(2f+3)=2(5f-1)/4

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Solution for 5(2f+3)=2(5f-1)/4 equation:



5(2f+3)=2(5f-1)/4
We move all terms to the left:
5(2f+3)-(2(5f-1)/4)=0
We multiply parentheses
10f-(2(5f-1)/4)+15=0
We multiply all the terms by the denominator
10f*4)-(2(5f-1)+15*4)=0
We add all the numbers together, and all the variables
10f*4)-(2(5f-1)=0
Wy multiply elements
40f^2=0
a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{80}=0$

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