5(2f+3)=2(5f-1)/4

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Solution for 5(2f+3)=2(5f-1)/4 equation: 



5(2f+3)=2(5f-1)/4

We move all terms to the left:

5(2f+3)-(2(5f-1)/4)=0

We multiply parentheses

10f-(2(5f-1)/4)+15=0

We multiply all the terms by the denominator


10f*4)-(2(5f-1)+15*4)=0

We add all the numbers together, and all the variables

10f*4)-(2(5f-1)=0

Wy multiply elements

40f^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{80}=0$

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