5(2f+6)=-4(-5-2f)+3f

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Solution for 5(2f+6)=-4(-5-2f)+3f equation: 



5(2f+6)=-4(-5-2f)+3f

We move all terms to the left:

5(2f+6)-(-4(-5-2f)+3f)=0

We add all the numbers together, and all the variables

5(2f+6)-(-4(-2f-5)+3f)=0

We multiply parentheses

10f-(-4(-2f-5)+3f)+30=0



We calculate terms in parentheses: -(-4(-2f-5)+3f), so:

-4(-2f-5)+3f

We add all the numbers together, and all the variables

3f-4(-2f-5)

We multiply parentheses

3f+8f+20

We add all the numbers together, and all the variables

11f+20

Back to the equation:

-(11f+20)



We get rid of parentheses

10f-11f-20+30=0

We add all the numbers together, and all the variables

-1f+10=0

We move all terms containing f to the left, all other terms to the right

-f=-10

f=-10/-1

f=+10

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