5(2f-2)=5f+20

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Solution for 5(2f-2)=5f+20 equation: 



5(2f-2)=5f+20

We move all terms to the left:

5(2f-2)-(5f+20)=0

We multiply parentheses

10f-(5f+20)-10=0

We get rid of parentheses

10f-5f-20-10=0

We add all the numbers together, and all the variables

5f-30=0

We move all terms containing f to the left, all other terms to the right

5f=30

f=30/5

f=6

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