5(2f-3)=2(4-6f)

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Solution for 5(2f-3)=2(4-6f) equation: 



5(2f-3)=2(4-6f)

We move all terms to the left:

5(2f-3)-(2(4-6f))=0

We add all the numbers together, and all the variables

5(2f-3)-(2(-6f+4))=0

We multiply parentheses

10f-(2(-6f+4))-15=0



We calculate terms in parentheses: -(2(-6f+4)), so:

2(-6f+4)

We multiply parentheses

-12f+8

Back to the equation:

-(-12f+8)



We get rid of parentheses

10f+12f-8-15=0

We add all the numbers together, and all the variables

22f-23=0

We move all terms containing f to the left, all other terms to the right

22f=23

f=23/22

f=1+1/22

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