5(2f-4(p+5))=25

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Solution for 5(2f-4(p+5))=25 equation:


Simplifying
5(2f + -4(p + 5)) = 25

Reorder the terms:
5(2f + -4(5 + p)) = 25
5(2f + (5 * -4 + p * -4)) = 25
5(2f + (-20 + -4p)) = 25

Reorder the terms:
5(-20 + 2f + -4p) = 25
(-20 * 5 + 2f * 5 + -4p * 5) = 25
(-100 + 10f + -20p) = 25

Solving
-100 + 10f + -20p = 25

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '100' to each side of the equation.
-100 + 10f + 100 + -20p = 25 + 100

Reorder the terms:
-100 + 100 + 10f + -20p = 25 + 100

Combine like terms: -100 + 100 = 0
0 + 10f + -20p = 25 + 100
10f + -20p = 25 + 100

Combine like terms: 25 + 100 = 125
10f + -20p = 125

Add '20p' to each side of the equation.
10f + -20p + 20p = 125 + 20p

Combine like terms: -20p + 20p = 0
10f + 0 = 125 + 20p
10f = 125 + 20p

Divide each side by '10'.
f = 12.5 + 2p

Simplifying
f = 12.5 + 2p

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