5(2f-4)=10f-20

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Solution for 5(2f-4)=10f-20 equation: 



5(2f-4)=10f-20

We move all terms to the left:

5(2f-4)-(10f-20)=0

We multiply parentheses

10f-(10f-20)-20=0

We get rid of parentheses

10f-10f+20-20=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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