5(2f=3)=2(5f-1)

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Solution for 5(2f=3)=2(5f-1) equation: 



5(2f=3)=2(5f-1)

We move all terms to the left:

5(2f-(3))=0

We multiply parentheses

10f-15=0

We move all terms containing f to the left, all other terms to the right

10f=15

f=15/10

f=1+1/2

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