5(2h-3)=6(h-2)

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Solution for 5(2h-3)=6(h-2) equation: 



5(2h-3)=6(h-2)

We move all terms to the left:

5(2h-3)-(6(h-2))=0

We multiply parentheses

10h-(6(h-2))-15=0



We calculate terms in parentheses: -(6(h-2)), so:

6(h-2)

We multiply parentheses

6h-12

Back to the equation:

-(6h-12)



We get rid of parentheses

10h-6h+12-15=0

We add all the numbers together, and all the variables

4h-3=0

We move all terms containing h to the left, all other terms to the right

4h=3

h=3/4

h=3/4

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