5(2i+3j)+4(3i-3j)=

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Solution for 5(2i+3j)+4(3i-3j)= equation:


Simplifying
5(2i + 3j) + 4(3i + -3j) = 0
(2i * 5 + 3j * 5) + 4(3i + -3j) = 0
(10i + 15j) + 4(3i + -3j) = 0
10i + 15j + (3i * 4 + -3j * 4) = 0
10i + 15j + (12i + -12j) = 0

Reorder the terms:
10i + 12i + 15j + -12j = 0

Combine like terms: 10i + 12i = 22i
22i + 15j + -12j = 0

Combine like terms: 15j + -12j = 3j
22i + 3j = 0

Solving
22i + 3j = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3j' to each side of the equation.
22i + 3j + -3j = 0 + -3j

Combine like terms: 3j + -3j = 0
22i + 0 = 0 + -3j
22i = 0 + -3j
Remove the zero:
22i = -3j

Divide each side by '22'.
i = -0.1363636364j

Simplifying
i = -0.1363636364j

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