5(2k+1)=3(k+4)5

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Solution for 5(2k+1)=3(k+4)5 equation: 



5(2k+1)=3(k+4)5

We move all terms to the left:

5(2k+1)-(3(k+4)5)=0

We multiply parentheses

10k-(3(k+4)5)+5=0



We calculate terms in parentheses: -(3(k+4)5), so:

3(k+4)5

We multiply parentheses

15k+60

Back to the equation:

-(15k+60)



We get rid of parentheses

10k-15k-60+5=0

We add all the numbers together, and all the variables

-5k-55=0

We move all terms containing k to the left, all other terms to the right

-5k=55

k=55/-5

k=-11

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