5(2k+3)-2(k-8)=3(2k+4)+k-2

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Solution for 5(2k+3)-2(k-8)=3(2k+4)+k-2 equation: 



5(2k+3)-2(k-8)=3(2k+4)+k-2

We move all terms to the left:

5(2k+3)-2(k-8)-(3(2k+4)+k-2)=0

We multiply parentheses

10k-2k-(3(2k+4)+k-2)+15+16=0



We calculate terms in parentheses: -(3(2k+4)+k-2), so:

3(2k+4)+k-2

We add all the numbers together, and all the variables

k+3(2k+4)-2

We multiply parentheses

k+6k+12-2

We add all the numbers together, and all the variables

7k+10

Back to the equation:

-(7k+10)



We add all the numbers together, and all the variables

8k-(7k+10)+31=0

We get rid of parentheses

8k-7k-10+31=0

We add all the numbers together, and all the variables

k+21=0

We move all terms containing k to the left, all other terms to the right

k=-21

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