5(2k+3)-2(k-9)=3(2k+4)+k-2

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Solution for 5(2k+3)-2(k-9)=3(2k+4)+k-2 equation:


5(2k+3)-2(k-9)=3(2k+4)+k-2

We simplify the equation to the form, which is simple to understand 
5(2k+3)-2(k-9)=3(2k+4)+k-2

Reorder the terms in parentheses
+(+10k+15)-2*(k-9)=3*(2k+4)+k-2

Remove unnecessary parentheses
+10k+15-2+*(+k-9+)=+3+*(+2k+4+)+k-2

Reorder the terms in parentheses
+10k+15+(-2k+18)=3*(2k+4)+k-2

Remove unnecessary parentheses
+10k+15-2k+18=+3+*(+2k+4+)+k-2

Reorder the terms in parentheses
+10k+15-2k+18=+(+6k+12)+k-2

Remove unnecessary parentheses
+10k+15-2k+18=+6k+12+k-2

We move all terms containing k to the left and all other terms to the right. 
+10k-2k-6k-1k=+12-2-15-18

We simplify left and right side of the equation. 
+1k=-23

We divide both sides of the equation by 1 to get k. 
k=-23

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