5(2k+3)=3(4K-2)-2k

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Solution for 5(2k+3)=3(4K-2)-2k equation: 



5(2k+3)=3(4-2)-2k

We move all terms to the left:

5(2k+3)-(3(4-2)-2k)=0

We add all the numbers together, and all the variables

5(2k+3)-(32-2k)=0

We multiply parentheses

10k-(32-2k)+15=0

We get rid of parentheses

10k+2k-32+15=0

We add all the numbers together, and all the variables

12k-17=0

We move all terms containing k to the left, all other terms to the right

12k=17

k=17/12

k=1+5/12

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