5(2k-1)+3k=6k+4(7k-5)

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Solution for 5(2k-1)+3k=6k+4(7k-5) equation:



5(2k-1)+3k=6k+4(7k-5)
We move all terms to the left:
5(2k-1)+3k-(6k+4(7k-5))=0
We add all the numbers together, and all the variables
3k+5(2k-1)-(6k+4(7k-5))=0
We multiply parentheses
3k+10k-(6k+4(7k-5))-5=0
We calculate terms in parentheses: -(6k+4(7k-5)), so:
6k+4(7k-5)
We multiply parentheses
6k+28k-20
We add all the numbers together, and all the variables
34k-20
Back to the equation:
-(34k-20)
We add all the numbers together, and all the variables
13k-(34k-20)-5=0
We get rid of parentheses
13k-34k+20-5=0
We add all the numbers together, and all the variables
-21k+15=0
We move all terms containing k to the left, all other terms to the right
-21k=-15
k=-15/-21
k=5/7

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