5(2k-3)=2(k-2)+5

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Solution for 5(2k-3)=2(k-2)+5 equation: 



5(2k-3)=2(k-2)+5

We move all terms to the left:

5(2k-3)-(2(k-2)+5)=0

We multiply parentheses

10k-(2(k-2)+5)-15=0



We calculate terms in parentheses: -(2(k-2)+5), so:

2(k-2)+5

We multiply parentheses

2k-4+5

We add all the numbers together, and all the variables

2k+1

Back to the equation:

-(2k+1)



We get rid of parentheses

10k-2k-1-15=0

We add all the numbers together, and all the variables

8k-16=0

We move all terms containing k to the left, all other terms to the right

8k=16

k=16/8

k=2

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