5(2m+1)-3(4m-2)=99

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Solution for 5(2m+1)-3(4m-2)=99 equation: 



5(2m+1)-3(4m-2)=99

We move all terms to the left:

5(2m+1)-3(4m-2)-(99)=0

We multiply parentheses

10m-12m+5+6-99=0

We add all the numbers together, and all the variables

-2m-88=0

We move all terms containing m to the left, all other terms to the right

-2m=88

m=88/-2

m=-44

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