5(2m+1)=3(4m-2)=99

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Solution for 5(2m+1)=3(4m-2)=99 equation: 



5(2m+1)=3(4m-2)=99

We move all terms to the left:

5(2m+1)-(3(4m-2))=0

We multiply parentheses

10m-(3(4m-2))+5=0



We calculate terms in parentheses: -(3(4m-2)), so:

3(4m-2)

We multiply parentheses

12m-6

Back to the equation:

-(12m-6)



We get rid of parentheses

10m-12m+6+5=0

We add all the numbers together, and all the variables

-2m+11=0

We move all terms containing m to the left, all other terms to the right

-2m=-11

m=-11/-2

m=5+1/2

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