5(2m+2)+6(3m-5)=64

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Solution for 5(2m+2)+6(3m-5)=64 equation: 



5(2m+2)+6(3m-5)=64

We move all terms to the left:

5(2m+2)+6(3m-5)-(64)=0

We multiply parentheses

10m+18m+10-30-64=0

We add all the numbers together, and all the variables

28m-84=0

We move all terms containing m to the left, all other terms to the right

28m=84

m=84/28

m=3

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