5(2m+3)-(1-2m)=(3(3+2m)-(3-m))

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Solution for 5(2m+3)-(1-2m)=(3(3+2m)-(3-m)) equation: 



5(2m+3)-(1-2m)=(3(3+2m)-(3-m))

We move all terms to the left:

5(2m+3)-(1-2m)-((3(3+2m)-(3-m)))=0

We add all the numbers together, and all the variables

5(2m+3)-(-2m+1)-((3(2m+3)-(-1m+3)))=0

We multiply parentheses

10m-(-2m+1)-((3(2m+3)-(-1m+3)))+15=0

We get rid of parentheses

10m+2m-((3(2m+3)-(-1m+3)))-1+15=0



We calculate terms in parentheses: -((3(2m+3)-(-1m+3))), so:

(3(2m+3)-(-1m+3))



We calculate terms in parentheses: +(3(2m+3)-(-1m+3)), so:

3(2m+3)-(-1m+3)

We multiply parentheses

6m-(-1m+3)+9

We get rid of parentheses

6m+1m-3+9

We add all the numbers together, and all the variables

7m+6

Back to the equation:

+(7m+6)



We get rid of parentheses

7m+6

Back to the equation:

-(7m+6)



We add all the numbers together, and all the variables

12m-(7m+6)+14=0

We get rid of parentheses

12m-7m-6+14=0

We add all the numbers together, and all the variables

5m+8=0

We move all terms containing m to the left, all other terms to the right

5m=-8

m=-8/5

m=-1+3/5

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