5(2m+3)-2m=4(m-2)-1

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Solution for 5(2m+3)-2m=4(m-2)-1 equation: 



5(2m+3)-2m=4(m-2)-1

We move all terms to the left:

5(2m+3)-2m-(4(m-2)-1)=0

We add all the numbers together, and all the variables

-2m+5(2m+3)-(4(m-2)-1)=0

We multiply parentheses

-2m+10m-(4(m-2)-1)+15=0



We calculate terms in parentheses: -(4(m-2)-1), so:

4(m-2)-1

We multiply parentheses

4m-8-1

We add all the numbers together, and all the variables

4m-9

Back to the equation:

-(4m-9)



We add all the numbers together, and all the variables

8m-(4m-9)+15=0

We get rid of parentheses

8m-4m+9+15=0

We add all the numbers together, and all the variables

4m+24=0

We move all terms containing m to the left, all other terms to the right

4m=-24

m=-24/4

m=-6

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