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5(2m-4)=3(3m-6)+m-2
We move all terms to the left:
5(2m-4)-(3(3m-6)+m-2)=0
We multiply parentheses
10m-(3(3m-6)+m-2)-20=0
We calculate terms in parentheses: -(3(3m-6)+m-2), so:We get rid of parentheses
3(3m-6)+m-2
We add all the numbers together, and all the variables
m+3(3m-6)-2
We multiply parentheses
m+9m-18-2
We add all the numbers together, and all the variables
10m-20
Back to the equation:
-(10m-20)
10m-10m+20-20=0
We add all the numbers together, and all the variables
=0
m=0/1
m=0
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