5(2n+1)=7(4n+5)+7

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Solution for 5(2n+1)=7(4n+5)+7 equation: 



5(2n+1)=7(4n+5)+7

We move all terms to the left:

5(2n+1)-(7(4n+5)+7)=0

We multiply parentheses

10n-(7(4n+5)+7)+5=0



We calculate terms in parentheses: -(7(4n+5)+7), so:

7(4n+5)+7

We multiply parentheses

28n+35+7

We add all the numbers together, and all the variables

28n+42

Back to the equation:

-(28n+42)



We get rid of parentheses

10n-28n-42+5=0

We add all the numbers together, and all the variables

-18n-37=0

We move all terms containing n to the left, all other terms to the right

-18n=37

n=37/-18

n=-2+1/18

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