5(2n+3)=7(3n+1)+8

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Solution for 5(2n+3)=7(3n+1)+8 equation: 



5(2n+3)=7(3n+1)+8

We move all terms to the left:

5(2n+3)-(7(3n+1)+8)=0

We multiply parentheses

10n-(7(3n+1)+8)+15=0



We calculate terms in parentheses: -(7(3n+1)+8), so:

7(3n+1)+8

We multiply parentheses

21n+7+8

We add all the numbers together, and all the variables

21n+15

Back to the equation:

-(21n+15)



We get rid of parentheses

10n-21n-15+15=0

We add all the numbers together, and all the variables

-11n=0

n=0/-11

n=0

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