5(2n+4)=7(4n+5)+1

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Solution for 5(2n+4)=7(4n+5)+1 equation: 



5(2n+4)=7(4n+5)+1

We move all terms to the left:

5(2n+4)-(7(4n+5)+1)=0

We multiply parentheses

10n-(7(4n+5)+1)+20=0



We calculate terms in parentheses: -(7(4n+5)+1), so:

7(4n+5)+1

We multiply parentheses

28n+35+1

We add all the numbers together, and all the variables

28n+36

Back to the equation:

-(28n+36)



We get rid of parentheses

10n-28n-36+20=0

We add all the numbers together, and all the variables

-18n-16=0

We move all terms containing n to the left, all other terms to the right

-18n=16

n=16/-18

n=-8/9

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