5(2n-3)=7(2n-5)+8

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Solution for 5(2n-3)=7(2n-5)+8 equation:



5(2n-3)=7(2n-5)+8
We move all terms to the left:
5(2n-3)-(7(2n-5)+8)=0
We multiply parentheses
10n-(7(2n-5)+8)-15=0
We calculate terms in parentheses: -(7(2n-5)+8), so:
7(2n-5)+8
We multiply parentheses
14n-35+8
We add all the numbers together, and all the variables
14n-27
Back to the equation:
-(14n-27)
We get rid of parentheses
10n-14n+27-15=0
We add all the numbers together, and all the variables
-4n+12=0
We move all terms containing n to the left, all other terms to the right
-4n=-12
n=-12/-4
n=+3

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