5(2p-6)+10=6(p+3)+4(2p-1)

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Solution for 5(2p-6)+10=6(p+3)+4(2p-1) equation: 



5(2p-6)+10=6(p+3)+4(2p-1)

We move all terms to the left:

5(2p-6)+10-(6(p+3)+4(2p-1))=0

We multiply parentheses

10p-(6(p+3)+4(2p-1))-30+10=0



We calculate terms in parentheses: -(6(p+3)+4(2p-1)), so:

6(p+3)+4(2p-1)

We multiply parentheses

6p+8p+18-4

We add all the numbers together, and all the variables

14p+14

Back to the equation:

-(14p+14)



We add all the numbers together, and all the variables

10p-(14p+14)-20=0

We get rid of parentheses

10p-14p-14-20=0

We add all the numbers together, and all the variables

-4p-34=0

We move all terms containing p to the left, all other terms to the right

-4p=34

p=34/-4

p=-8+1/2

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