5(2q+4)=3(q-2)

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Solution for 5(2q+4)=3(q-2) equation: 



5(2q+4)=3(q-2)

We move all terms to the left:

5(2q+4)-(3(q-2))=0

We multiply parentheses

10q-(3(q-2))+20=0



We calculate terms in parentheses: -(3(q-2)), so:

3(q-2)

We multiply parentheses

3q-6

Back to the equation:

-(3q-6)



We get rid of parentheses

10q-3q+6+20=0

We add all the numbers together, and all the variables

7q+26=0

We move all terms containing q to the left, all other terms to the right

7q=-26

q=-26/7

q=-3+5/7

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