5(2q-6)=3(-7+4q)

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Solution for 5(2q-6)=3(-7+4q) equation:



5(2q-6)=3(-7+4q)
We move all terms to the left:
5(2q-6)-(3(-7+4q))=0
We add all the numbers together, and all the variables
5(2q-6)-(3(4q-7))=0
We multiply parentheses
10q-(3(4q-7))-30=0
We calculate terms in parentheses: -(3(4q-7)), so:
3(4q-7)
We multiply parentheses
12q-21
Back to the equation:
-(12q-21)
We get rid of parentheses
10q-12q+21-30=0
We add all the numbers together, and all the variables
-2q-9=0
We move all terms containing q to the left, all other terms to the right
-2q=9
q=9/-2
q=-4+1/2

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