5(2q-6)=3(-7+4q)

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Solution for 5(2q-6)=3(-7+4q) equation: 



5(2q-6)=3(-7+4q)

We move all terms to the left:

5(2q-6)-(3(-7+4q))=0

We add all the numbers together, and all the variables

5(2q-6)-(3(4q-7))=0

We multiply parentheses

10q-(3(4q-7))-30=0



We calculate terms in parentheses: -(3(4q-7)), so:

3(4q-7)

We multiply parentheses

12q-21

Back to the equation:

-(12q-21)



We get rid of parentheses

10q-12q+21-30=0

We add all the numbers together, and all the variables

-2q-9=0

We move all terms containing q to the left, all other terms to the right

-2q=9

q=9/-2

q=-4+1/2

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