5(2r+1)-3(2r-1)=12-2(r-3)

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Solution for 5(2r+1)-3(2r-1)=12-2(r-3) equation: 



5(2r+1)-3(2r-1)=12-2(r-3)

We move all terms to the left:

5(2r+1)-3(2r-1)-(12-2(r-3))=0

We multiply parentheses

10r-6r-(12-2(r-3))+5+3=0



We calculate terms in parentheses: -(12-2(r-3)), so:

12-2(r-3)

determiningTheFunctionDomain
-2(r-3)+12

We multiply parentheses

-2r+6+12

We add all the numbers together, and all the variables

-2r+18

Back to the equation:

-(-2r+18)



We add all the numbers together, and all the variables

4r-(-2r+18)+8=0

We get rid of parentheses

4r+2r-18+8=0

We add all the numbers together, and all the variables

6r-10=0

We move all terms containing r to the left, all other terms to the right

6r=10

r=10/6

r=1+2/3

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