5(2r+4)=3(2r+9)+4r-7

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Solution for 5(2r+4)=3(2r+9)+4r-7 equation: 


Simplifying
5(2r + 4) = 3(2r + 9) + 4r + -7

Reorder the terms:
5(4 + 2r) = 3(2r + 9) + 4r + -7
(4 * 5 + 2r * 5) = 3(2r + 9) + 4r + -7
(20 + 10r) = 3(2r + 9) + 4r + -7

Reorder the terms:
20 + 10r = 3(9 + 2r) + 4r + -7
20 + 10r = (9 * 3 + 2r * 3) + 4r + -7
20 + 10r = (27 + 6r) + 4r + -7

Reorder the terms:
20 + 10r = 27 + -7 + 6r + 4r

Combine like terms: 27 + -7 = 20
20 + 10r = 20 + 6r + 4r

Combine like terms: 6r + 4r = 10r
20 + 10r = 20 + 10r

Add '-20' to each side of the equation.
20 + -20 + 10r = 20 + -20 + 10r

Combine like terms: 20 + -20 = 0
0 + 10r = 20 + -20 + 10r
10r = 20 + -20 + 10r

Combine like terms: 20 + -20 = 0
10r = 0 + 10r
10r = 10r

Add '-10r' to each side of the equation.
10r + -10r = 10r + -10r

Combine like terms: 10r + -10r = 0
0 = 10r + -10r

Combine like terms: 10r + -10r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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