5(2r-3)+6(4+r)=39

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Solution for 5(2r-3)+6(4+r)=39 equation: 



5(2r-3)+6(4+r)=39

We move all terms to the left:

5(2r-3)+6(4+r)-(39)=0

We add all the numbers together, and all the variables

5(2r-3)+6(r+4)-39=0

We multiply parentheses

10r+6r-15+24-39=0

We add all the numbers together, and all the variables

16r-30=0

We move all terms containing r to the left, all other terms to the right

16r=30

r=30/16

r=1+7/8

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