5(2r-3)+7(2-r)=3(r+2)-7

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Solution for 5(2r-3)+7(2-r)=3(r+2)-7 equation:


Simplifying
5(2r + -3) + 7(2 + -1r) = 3(r + 2) + -7

Reorder the terms:
5(-3 + 2r) + 7(2 + -1r) = 3(r + 2) + -7
(-3 * 5 + 2r * 5) + 7(2 + -1r) = 3(r + 2) + -7
(-15 + 10r) + 7(2 + -1r) = 3(r + 2) + -7
-15 + 10r + (2 * 7 + -1r * 7) = 3(r + 2) + -7
-15 + 10r + (14 + -7r) = 3(r + 2) + -7

Reorder the terms:
-15 + 14 + 10r + -7r = 3(r + 2) + -7

Combine like terms: -15 + 14 = -1
-1 + 10r + -7r = 3(r + 2) + -7

Combine like terms: 10r + -7r = 3r
-1 + 3r = 3(r + 2) + -7

Reorder the terms:
-1 + 3r = 3(2 + r) + -7
-1 + 3r = (2 * 3 + r * 3) + -7
-1 + 3r = (6 + 3r) + -7

Reorder the terms:
-1 + 3r = 6 + -7 + 3r

Combine like terms: 6 + -7 = -1
-1 + 3r = -1 + 3r

Add '1' to each side of the equation.
-1 + 1 + 3r = -1 + 1 + 3r

Combine like terms: -1 + 1 = 0
0 + 3r = -1 + 1 + 3r
3r = -1 + 1 + 3r

Combine like terms: -1 + 1 = 0
3r = 0 + 3r
3r = 3r

Add '-3r' to each side of the equation.
3r + -3r = 3r + -3r

Combine like terms: 3r + -3r = 0
0 = 3r + -3r

Combine like terms: 3r + -3r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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