5(2s+4+3s)-4=(s+7)

Solution for 5(2s+4+3s)-4=(s+7) equation:

5(2s+4+3s)-4=(s+7)

We move all terms to the left:

5(2s+4+3s)-4-((s+7))=0

We add all the numbers together, and all the variables

5(5s+4)-((s+7))-4=0

We multiply parentheses

25s-((s+7))+20-4=0


We calculate terms in parentheses: -((s+7)), so:

(s+7)

We get rid of parentheses

s+7

Back to the equation:

-(s+7)


We add all the numbers together, and all the variables

25s-(s+7)+16=0

We get rid of parentheses

25s-s-7+16=0

We add all the numbers together, and all the variables

24s+9=0

We move all terms containing s to the left, all other terms to the right

24s=-9

s=-9/24

s=-3/8