5(2s-1)-3(s+2);s=4

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Solution for 5(2s-1)-3(s+2);s=4 equation: 



5(2s-1)-3(s+2)s=4

We move all terms to the left:

5(2s-1)-3(s+2)s-(4)=0

We multiply parentheses

-3s^2+10s-6s-5-4=0

We add all the numbers together, and all the variables

-3s^2+4s-9=0

a = -3; b = 4; c = -9;
Δ = b2-4ac
Δ = 42-4·(-3)·(-9)
Δ = -92
Delta is less than zero, so there is no solution for the equation

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