5(2s-4)+13=4(s-3)-(2s+3)

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Solution for 5(2s-4)+13=4(s-3)-(2s+3) equation: 



5(2s-4)+13=4(s-3)-(2s+3)

We move all terms to the left:

5(2s-4)+13-(4(s-3)-(2s+3))=0

We multiply parentheses

10s-(4(s-3)-(2s+3))-20+13=0



We calculate terms in parentheses: -(4(s-3)-(2s+3)), so:

4(s-3)-(2s+3)

We multiply parentheses

4s-(2s+3)-12

We get rid of parentheses

4s-2s-3-12

We add all the numbers together, and all the variables

2s-15

Back to the equation:

-(2s-15)



We add all the numbers together, and all the variables

10s-(2s-15)-7=0

We get rid of parentheses

10s-2s+15-7=0

We add all the numbers together, and all the variables

8s+8=0

We move all terms containing s to the left, all other terms to the right

8s=-8

s=-8/8

s=-1

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