5(2t+1)+(-7t+28)=

Solution for 5(2t+1)+(-7t+28)= equation:

Simplifying
5(2t + 1) + (-7t + 28) = 0

Reorder the terms:
5(1 + 2t) + (-7t + 28) = 0
(1 * 5 + 2t * 5) + (-7t + 28) = 0
(5 + 10t) + (-7t + 28) = 0

Reorder the terms:
5 + 10t + (28 + -7t) = 0

Remove parenthesis around (28 + -7t)
5 + 10t + 28 + -7t = 0

Reorder the terms:
5 + 28 + 10t + -7t = 0

Combine like terms: 5 + 28 = 33
33 + 10t + -7t = 0

Combine like terms: 10t + -7t = 3t
33 + 3t = 0

Solving
33 + 3t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-33' to each side of the equation.
33 + -33 + 3t = 0 + -33

Combine like terms: 33 + -33 = 0
0 + 3t = 0 + -33
3t = 0 + -33

Combine like terms: 0 + -33 = -33
3t = -33

Divide each side by '3'.
t = -11

Simplifying
t = -11