5(2t+1)+(-7t+28)=0

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Solution for 5(2t+1)+(-7t+28)=0 equation:



5(2t+1)+(-7t+28)=0
We multiply parentheses
10t+(-7t+28)+5=0
We get rid of parentheses
10t-7t+28+5=0
We add all the numbers together, and all the variables
3t+33=0
We move all terms containing t to the left, all other terms to the right
3t=-33
t=-33/3
t=-11

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