5(2t+1)-8=4t-3(1-2t)

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Solution for 5(2t+1)-8=4t-3(1-2t) equation:


Simplifying
5(2t + 1) + -8 = 4t + -3(1 + -2t)

Reorder the terms:
5(1 + 2t) + -8 = 4t + -3(1 + -2t)
(1 * 5 + 2t * 5) + -8 = 4t + -3(1 + -2t)
(5 + 10t) + -8 = 4t + -3(1 + -2t)

Reorder the terms:
5 + -8 + 10t = 4t + -3(1 + -2t)

Combine like terms: 5 + -8 = -3
-3 + 10t = 4t + -3(1 + -2t)
-3 + 10t = 4t + (1 * -3 + -2t * -3)
-3 + 10t = 4t + (-3 + 6t)

Reorder the terms:
-3 + 10t = -3 + 4t + 6t

Combine like terms: 4t + 6t = 10t
-3 + 10t = -3 + 10t

Add '3' to each side of the equation.
-3 + 3 + 10t = -3 + 3 + 10t

Combine like terms: -3 + 3 = 0
0 + 10t = -3 + 3 + 10t
10t = -3 + 3 + 10t

Combine like terms: -3 + 3 = 0
10t = 0 + 10t
10t = 10t

Add '-10t' to each side of the equation.
10t + -10t = 10t + -10t

Combine like terms: 10t + -10t = 0
0 = 10t + -10t

Combine like terms: 10t + -10t = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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