5(2t+1)-8=t-(t+2)

Solution for 5(2t+1)-8=t-(t+2) equation:

Simplifying
5(2t + 1) + -8 = t + -1(t + 2)

Reorder the terms:
5(1 + 2t) + -8 = t + -1(t + 2)
(1 * 5 + 2t * 5) + -8 = t + -1(t + 2)
(5 + 10t) + -8 = t + -1(t + 2)

Reorder the terms:
5 + -8 + 10t = t + -1(t + 2)

Combine like terms: 5 + -8 = -3
-3 + 10t = t + -1(t + 2)

Reorder the terms:
-3 + 10t = t + -1(2 + t)
-3 + 10t = t + (2 * -1 + t * -1)
-3 + 10t = t + (-2 + -1t)

Reorder the terms:
-3 + 10t = -2 + t + -1t

Combine like terms: t + -1t = 0
-3 + 10t = -2 + 0
-3 + 10t = -2

Solving
-3 + 10t = -2

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 10t = -2 + 3

Combine like terms: -3 + 3 = 0
0 + 10t = -2 + 3
10t = -2 + 3

Combine like terms: -2 + 3 = 1
10t = 1

Divide each side by '10'.
t = 0.1

Simplifying
t = 0.1