5(2t+3)=3(7-2t)

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Solution for 5(2t+3)=3(7-2t) equation:



5(2t+3)=3(7-2t)
We move all terms to the left:
5(2t+3)-(3(7-2t))=0
We add all the numbers together, and all the variables
5(2t+3)-(3(-2t+7))=0
We multiply parentheses
10t-(3(-2t+7))+15=0
We calculate terms in parentheses: -(3(-2t+7)), so:
3(-2t+7)
We multiply parentheses
-6t+21
Back to the equation:
-(-6t+21)
We get rid of parentheses
10t+6t-21+15=0
We add all the numbers together, and all the variables
16t-6=0
We move all terms containing t to the left, all other terms to the right
16t=6
t=6/16
t=3/8

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