5(2t-1)+18=3(3t+2)

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Solution for 5(2t-1)+18=3(3t+2) equation: 



5(2t-1)+18=3(3t+2)

We move all terms to the left:

5(2t-1)+18-(3(3t+2))=0

We multiply parentheses

10t-(3(3t+2))-5+18=0



We calculate terms in parentheses: -(3(3t+2)), so:

3(3t+2)

We multiply parentheses

9t+6

Back to the equation:

-(9t+6)



We add all the numbers together, and all the variables

10t-(9t+6)+13=0

We get rid of parentheses

10t-9t-6+13=0

We add all the numbers together, and all the variables

t+7=0

We move all terms containing t to the left, all other terms to the right

t=-7

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